| 11 Aug 2024 |
|  Mic92 joined the room. | 03:49:24 |
| Mic92 | das_j: John Ericson I would like to apply for hydra commit access: https://github.com/nix-community/infra/pull/1349#discussion_r1712899387 | 03:50:17 |
| Mic92 | I haven't contributed anything but have been more of a user. However I know some Perl and I would like to integrate nix-eval-jobs into hydra to close the circle | 03:51:43 |
| Mic92 | * I haven't contributed anything but have been more of a user. In nix-community we have some smaller deployment that we use for real-world testing. However I know some Perl and I would like to integrate nix-eval-jobs into hydra to close the circle | 03:52:36 |
| Mic92 | * I haven't contributed anything to hydra but have been more of a user. In nix-community we have some smaller deployment that we use for real-world testing. However I know some Perl and I would like to integrate nix-eval-jobs into hydra to close the circle | 03:53:00 |
| Mic92 | Redacted or Malformed Event | 12:29:31 |
| Mic92 | Interesting I cannot see my own message here | 12:30:20 |
| 13 Aug 2024 |
 John Ericson | Mic92: back from travelling, I would support this! :) | 18:42:55 |
| 19 Aug 2024 |
|  @alejandrosame:matrix.org left the room. | 08:51:37 |
 das_j | Mic92: invite is coming up :) | 19:40:16 |
| das_j | Sorry for the long wait | 19:41:34 |
| Mic92 | No problem. I kept myself busy by cleaning up NixOS infra. | 19:51:41 |
| 21 Aug 2024 |
 hacker1024 | Is there a way to tell Hydra not to worry about specific outputs for a (declarative) jobset? E.g. a job's derivation has split out and debug outputs, but I only care about out. If out is available without debug, though, Hydra will still rebuild the derivation, because it tries to realize both output paths. | 08:15:14 |
| hacker1024 | * Is there a way to tell Hydra not to worry about specific outputs for a (declarative) jobset? E.g. a job's derivation has split out and debug outputs, but I only care about out. If out is already available without debug, though, Hydra will still rebuild the derivation, because it tries to realize both output paths. | 08:17:04 |
 Rick (Mindavi) | Not that I'm aware of, and how can hydra know out doesn't change? | 11:59:34 |
